Respuesta :
Answer:
a) Area of the telescope lens is [tex]$1.076391014 \times 10^{-5} \mathrm{ft}^{2}$[/tex]
b) Technician needs to clean the lens [tex]$1.83 \times 10^{3} s$[/tex].
Explanation:
a) The area of the lens is [tex]$6.439 \times 10^{3} \mathrm{~mm}^{2}$[/tex]
To convert it into [tex]$f t^{2}$[/tex]
[tex]$1 \mathrm{~mm}=0.00328084 \mathrm{ft}$[/tex]
[tex]$1 \mathrm{~mm}^{2}=(0.00328084)^{2} \mathrm{ft}^{2}$[/tex]
[tex]$1 \mathrm{~mm}^{2}=1.076391014 \times 10^{-5} \mathrm{ft}^{2}$[/tex]
So,
[tex]$6.439 \times 10^{3} \mathrm{~mm}^{2}=6.439 \times 10^{3} * 1.076391014 \times 10^{-5} \mathrm{ft}^{2} .$[/tex]
[tex]$6.439 \times 10^{3} \mathrm{~mm}^{2}=6.93088174 \times 10^{-2} \mathrm{ft}^{2}$[/tex]
b) Time required to polish a entire area of lens
[tex]$=6.439 \times 10^{3} \mathrm{~mm}^{2} \times \frac{43.5 \mathrm{~s}}{1.53 \times 10^{2} \mathrm{~mm}^{2}}$[/tex]
[tex]$=1.83 \times 10^{3} \mathrm{~s}$[/tex]
Learn more about scientific notation, refer:
- https://brainly.com/question/10401258
