Answer:
[tex]x=-\frac{5}{3}\quad \mathrm{or}\quad \:x=3[/tex]
Step-by-step explanation:
[tex]2\left|3x-2\right|=14[/tex]
⇒ Divide both sides by 2
[tex]\frac{2\left|3x-2\right|}{2}=\frac{14}{2}[/tex]
[tex]\left|3x-2\right|=7[/tex]
⇒ Now, apply absolute rule:- if |x|=a,a > a than x=a or x=-a
[tex]3x-2=-7\quad[/tex]
or...
[tex]3x-2=7[/tex]
Now,
[tex]3x-2=-7[/tex]
⇒ Add 2 to both sides:-
[tex]3x-2+2=-7+2[/tex]
[tex]3x=-5[/tex]
⇒ Divide both sides by 3:-
[tex]\frac{3x}{3}=\frac{-5}{3}[/tex]
[tex]x=-\frac{5}{3}[/tex]
[tex]3x-2=7[/tex]
⇒ Add 2 to both sides:-
[tex]3x-2+2=7+2[/tex]
[tex]3x=9[/tex]
⇒ Divide both sides by 3:-
[tex]\frac{3x}{3}=\frac{9}{3}[/tex]
[tex]x=3[/tex]
OAmalOHopeO
