Answer:
Student 1 and Student 3
Step-by-step explanation:
For student 1: ✔
[tex] {x}^{2} = 64 \\ x = \sqrt{64} \\ x = {}^{ + } 8 \: \: and \: \: {}^{ - } 8[/tex]
For student 2: ❎
[tex] {x}^{3} = 1 \\ x = \sqrt[3]{1} \\ x = {}^{ + } 1[/tex]
For student 3: ✔
[tex] {x}^{2} = 9 \\ x = \sqrt{9} \\ x = {}^{ + } 3 \: \: and \: \: {}^{ - } 3[/tex]
For student 4: ❎
[tex] {x}^{3} = 216 \\ x = \sqrt[3]{216} \\ x = {}^{ + } 6[/tex]
