Respuesta :

s1m1

Answer:

Step-by-step explanation:

General equation of a line is y= mx+b,

where m is the slope and b is the y- intercept

For points (-5, -8) and (-4, -6) the slope is

m= difference in y / difference in x

m = [-6 - (-8)] / [-4 - (- 5)] = (-6+8)/(-4+5) = 2/1 =2

Now we know that y= 2x+b , to find b substitute the coordinate (x, y) with coordinate (-4, -6) -you could pick the other point if you want will work because both points are on the line.

-6 = 2(-4) +b , multiply

-6 = -8 + b, add 8 to both sides

-6+8 =b , add

2 =b

The equation of the line that passes through the points (-5, -8) and (-4, -6) is

y= 2x+2

khalifabrew

First of all, you will find the gradient. The formula for finding the gradient is y2-y1 /x2-x1. - 6--8/-4--5.If two negatives meet they change to positive. - 6+8/-4+5=2/1,therefore the gradient is 2,after that then you will find the equation of the line. The formula for finding the equation of the line is y-y1=m(x-x1). y-(-8)=m(x--5),y+8=2(x+5),y+8=2x+10,y=2x+2.

Otras preguntas