Respuesta :

caylus

Answer: 2600

Step-by-step explanation:

[tex]u_1=3\\u_2=5=3+2=3+2*(2-1)\\u_3=7=5+2=3+2*2=3+2*(3-1)\\u_4=9=3+2*3=3+2*(4-1)\\...\\u_n=3+2*(n-1)\\\\u_{50}=3+2*49=101\\\\\displaystyle \sum_{i=1}^{50}(3+2*i)=\dfrac{3+101}{2} *50=2600\\[/tex]

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