seemeha
seemeha
27-08-2021
Physics
contestada
xy+4z=
X=2
Y=2
Z=3
Solve for
Respuesta :
clockhart011
clockhart011
27-08-2021
Answer:
x×y=2×2=4. 4×z=4×3=12. 4+12=16
Answer Link
ambitious3161
ambitious3161
27-08-2021
X = 12
Y = 2
Z = 3
Put in xy+4z
12 x 2 + 4 x 3
=> 24 + 12
=> 36 Ans
Answer Link
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