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What is the solution to x 3 + x 2 ≤ 10x – 8?

A. {–4, 1, 2}
B. (–ꝏ, –4]
C. (–ꝏ, –4) U [1, 2]
D.(–ꝏ, –4] U [1, 2]

Respuesta :

Answer:

C or D since both are the same

Step-by-step explanation:

[tex]x^3+x^2\leq 10x-8\\x^3+x^2-10x+8\leq 0\\(x^2+2x-8)(x-1)\leq 0\\(x+4)(x-2)(x-1)\leq 0[/tex]

So

[tex]x\leq -4 \text{ or } 1\leq x\leq 2[/tex]

The correct answer to the problem is D.

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