Answer:
see explanation
Step-by-step explanation:
Using the rule of exponents
[tex]\frac{1}{a^{m} }[/tex] ⇔ [tex]a^{-m}[/tex]
64 = [tex]2^{6}[/tex] , then
[tex]2^{p}[/tex] = [tex]\frac{1}{64}[/tex] = [tex]\frac{1}{2^{6} }[/tex] = [tex]2^{-6}[/tex]
Since the bases on both sides are equal, both 2, then equate exponents
p = - 6
