Answer:
The appropriate answer is "[tex]0.657 \ mins/JU-4s[/tex]".
Explanation:
Given:
Demand,
= 1325 JU-4s
1 day = 2 shifts
Assuming a shift is of 8 hours duration.
then,
[tex]1 \ shift = (8\times 60)-(20+25)[/tex]
[tex]=480-45[/tex]
[tex]=435 \ mins[/tex]
Total day mins,
= [tex]435\times 2[/tex]
= [tex]870 \ mins[/tex]
hence,
The average throughput rate will be:
= [tex]\frac{870 \ mins}{1325 \ JU-4s}[/tex]
= [tex]0.657 \ mins/JU-4s[/tex]
