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An just finished taking statistics, and wants to do a survey on the average salary of Spring 2019 HCC graduates. She calculates that the standard error of the mean is $128.13 after she surveyed a group of students who reported an annual income of $43,650 and she knows the population standard deviation is $2,050, how many students were randomly sampled by An?

Respuesta :

Cricetus

Answer:

The appropriate answer is "256".

Step-by-step explanation:

Given:

Standard error,

SE = 128.13

Standard deviation,

[tex]\sigma[/tex] = $2050

As we know,

⇒ [tex]SE = \frac{\sigma}{\sqrt{n} }[/tex]

or,

⇒ [tex]\sqrt{n}= \frac{\sigma}{SE}[/tex]

By substituting the values, we get

         [tex]=\frac{2050}{128.13}[/tex]

         [tex]=\frac{205000}{12813}[/tex]

     [tex]n = (\frac{205000}{12813} )^2[/tex]

         [tex]=255.98[/tex]

or,

         [tex]=256[/tex]

   

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