Answer:
[tex]3\left(8-4x\right)<6\left(x-5\right)[/tex]
[tex]3(8-4x)=241-2x[/tex]
[tex]6(x-5)=6x-30[/tex]
[tex]24-12x<6x-30[/tex]
Subtract 24 from both sides
[tex]-12x<6x-54[/tex]
Now, subtract 6x from both sides
[tex]-18x<-54[/tex]
Multiply both sides by -1
[tex]18x>54[/tex]
Divide 18 from both sides
[tex]x>3[/tex]
OAmalOHopeO
