Respuesta :

Hi there!  

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I believe your answer is:  

[tex]x < 1[/tex]

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Here’s why:  

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[tex]\boxed{\text{Solving for 'x'...}}\\\\3(5+x)<18\\----------------\\\rightarrow 15 + 3x < 18\\\\\rightarrow 3x + 15 < 18\\\\\rightarrow 3x + 15 - 15 < 18 - 15\\\\\rightarrow 3x < 3\\\\\rightarrow \frac{3x<3}{3}\\\\\rightarrow \boxed{x < 1}[/tex]

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Hope this helps you. I apologize if it’s incorrect.  

SneakySnek131

Answer:

x  <  1  OR  ( − ∞ , 1 )

Step-by-step explanation:

Divide each term by 3

5  +  x  <  6

Subtract  5  from both sides.

x  <  6  −  5

Subtract  5  from  6 .

x  <  1

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