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In the adjoining fig. In a circle with centre C and chord DE ,ahe CF perpendicular to chord DE.If diameter of a circle is 20cm and DE=16cm,then CF=?GIVE REASON​

In the adjoining fig In a circle with centre C and chord DE ahe CF perpendicular to chord DEIf diameter of a circle is 20cm and DE16cmthen CFGIVE REASON class=

Respuesta :

DC=CF

  • Diameter=20cm
  • Radius=20/2=10cm

We know

[tex]\boxed{\sf L=\dfrac{\theta}{180}\times πr}[/tex]

[tex]\\ \large\sf\longmapsto L=\dfrac{90}{180}\times \dfrac{22}{7}\times 10[/tex]

[tex]\\ \large\sf\longmapsto L=\dfrac{1}{2}\times \dfrac{220}{7}[/tex]

[tex]\\ \large\sf\longmapsto L=\dfrac{110}{7}[/tex]

[tex]\\ \large\sf\longmapsto L=15.5[/tex]

Now

[tex]\\ \large\sf\longmapsto CF=L+r-DE[/tex]

[tex]\\ \large\sf\longmapsto CF=15.7+10-16[/tex]

[tex]\\ \large\sf\longmapsto CF=25.7-16[/tex]

[tex]\\ \large\sf\longmapsto CF=9.7cm[/tex]

HMMey

[tex]\large\sf\red{⟼L=18090×722×10}[/tex]

[tex]\begin{gathered}\\ \large\sf\red{ ⟼ L=\dfrac{1}{2}\times \dfrac{220}{7}}\end{gathered}[/tex]

[tex]\begin{gathered}{ \large\sf\red{⟼ L=\dfrac{110}{7}}\end{gathered}[/tex]

⟼ L=15.5

Now

⟼ CF=L+r−DE

⟼ CF=15.7+10−16

⟼ CF=25.7−16

⟼CF=9.7cm

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