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Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. A sample of 1100 bacteria selected from this population reached the size of 1177 bacteria in three hours. Find the hourly growth rate parameter. Note: This is a continuous exponential growth model. Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.

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Answer:

Rate = 10^(log[Ending Amount / Beginning Amount] ÷ time)  -1

Rate = 10^(log(1177 / 1100) ÷ time) -1

Rate = 10^(log( 1.07) ÷ 3) -1

Rate = 10^(0.029383777685 /3) -1

Rate = 10^(0.0097945926) -1

Rate = 1.0228091219 -1

Rate = .0228091219% / hour

Source http://www.1728.org/expgrwth.htm

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