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Calculate the heat change in calories for melting of 0.30 kg of water at 0*C. The
heat of fusion for water is 80 cal/g. The heat of vaporization of water is 540 cal/g.
The specific heat capacity of water is 1.00 cal/g*C.

Respuesta :

Answer: 24 kcal

Explanation:

Given

Mass of water [tex]m=0.3\ kg[/tex]

Temperature of water [tex]T_1=0^{\circ}[/tex]

Heat of fusion [tex]L_f=80\ cal/g[/tex]

Heat of vaporization [tex]L_v=540\ cal/g[/tex]

Specific heat of water [tex]c=1\ cal/g.^{\circ}C[/tex]

Heat require to melt the ice is

[tex]\Rightarrow Q=mL_f\\\Rightarrow Q=0.3\times 1000\times 80\\\Rightarrow Q=24000\ cal\ or\ 24\ kcal[/tex]

Thus, 24 kcal of heat is required to melt 0.3 kg of ice.

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