Answer:
240 N/m
Explanation:
Using the formula as follows:
U = ½kx²
Where;
U = elastic potential energy (J)
K = spring constant (N/m)
x = stretched displacement (m)
According to the information provided in this question,
U = 35J
x = 0.54m
k = ?
U = ½kx²
35 = ½ × k × 0.54²
35 = ½ × k × 0.2916
35 = 0.2916k/2
70 = 0.2916k
k = 70 ÷ 0.2916
k = 240.05
To 2s.f, the spring constant (k) = 240 N/m.
