Statesville's population in 2010 was about 24,500, and was growing by about 1% each year. continues, what will Statesville's population be in 2019? [Round to the nearest person.] ​

Respuesta :

Answer:

26,795 people

Step-by-step explanation:

P(x) = 24,500 × (1 + 0.01)^(2019-2010)

= 24,500 × (1.01)^9

= 24,500 × 1.0937

= 26,795 people

The required population of Statesville in the year 2019 will be 26,795.


Statesville's population in 2010 was about 24,500, growing by about 1% each year. Statesville's population be in 2019 to be determined.


what is an exponential function?

The function which is in format f(x) = a^x where, a is constant and x is variable,  the domain of this exponential function lies   ( -∞, ∞ ).  

Let Statesville's population in 2019 = x

Statesville's population in 2010 = 24500

Population growing by about 1% =  1/100
                                                  = 0.01

Difference in year n = 2019 - 2010
n = 9

Population in 2019,
x = 24500 *  ( 1 + 0.01 )^9
x = 24500 *  ( 1.01 )^9
x = 26, 795.295
To the nearest people x = 26,759
the population of Statesville in the year 2019 =  26,759
       

Thus,  the required population of Statesville in the year 2019 will be 26,795.

Learn more about exponential function here:

brainly.com/question/15352175

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