Respuesta :
Answer:
26,795 people
Step-by-step explanation:
P(x) = 24,500 × (1 + 0.01)^(2019-2010)
= 24,500 × (1.01)^9
= 24,500 × 1.0937
= 26,795 people
The required population of Statesville in the year 2019 will be 26,795.
Statesville's population in 2010 was about 24,500, growing by about 1% each year. Statesville's population be in 2019 to be determined.
what is an exponential function?
The function which is in format f(x) = a^x where, a is constant and x is variable, the domain of this exponential function lies ( -∞, ∞ ).
Let Statesville's population in 2019 = x
Statesville's population in 2010 = 24500
Population growing by about 1% = 1/100
= 0.01
Difference in year n = 2019 - 2010
n = 9
Population in 2019,
x = 24500 * ( 1 + 0.01 )^9
x = 24500 * ( 1.01 )^9
x = 26, 795.295
To the nearest people x = 26,759
the population of Statesville in the year 2019 = 26,759
Thus, the required population of Statesville in the year 2019 will be 26,795.
Learn more about exponential function here:
brainly.com/question/15352175
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