Given:
[tex]Domain\neq -1[/tex]
[tex]Range\neq 2[/tex]
To find:
The function for the given domain and range.
Solution:
A function is not defined for some values that makes the denominator equals to 0.
The denominator of functions in option A and C is [tex](x-1)[/tex].
[tex]x-1=0[/tex]
[tex]x=1[/tex]
So, the functions in option A and C are not defined for [tex]x=1[/tex] but defined for [tex]x=-1[/tex]. Therefore, the options A and C are incorrect.
In option B, the denominator is equal to [tex]x+1[/tex].
[tex]x+1=0[/tex]
[tex]x=-1[/tex]
So, the function is not defined for [tex]x=-1[/tex]. Thus, [tex]Domain\neq -1[/tex].
If degree of numerator and denominator are equal then the horizontal asymptote is [tex]y=\dfrac{a}{b}[/tex], where a is the leading coefficient of numerator and b is the leading coefficient of denominator.
In option B, the leading coefficient of numerator is 2 and the leading coefficient of denominator is 1. So, the horizontal asymptote is:
[tex]y=\dfrac{2}{1}[/tex]
[tex]y=2[/tex]
It means, the value of the function cannot be 2 at any point. So, [tex]Range\neq 2[/tex].
Hence, option B is correct.
