Answer:
The standard deviation for the number of people with the genetic mutation in such groups of 100=[tex]2.375[/tex]
Step-by-step explanation:-
We are given that
Total number of selected people, n=100
p=6%=0.06
We have to find the standard deviation for the number of people with the genetic mutation in such groups of 100.
Let X denote the number of people with the genetic mutation in such groups of 100.
[tex]\implies X\sim Bin(n=100,p=0.06)[/tex]
We know that
Standard deviation
=[tex]\sqrt{np(1-p)}[/tex]
Using the formula
Standard deviation
=[tex]\sqrt{100\times 0.06(1-0.06)}[/tex]
=[tex]\sqrt{6(0.94)}[/tex]
=[tex]2.375[/tex]
Hence, the standard deviation for the number of people with the genetic mutation in such groups of 100=[tex]2.375[/tex]
