Answer:
The sign of work will be negative.
Explanation:
The work of the system is given by:
[tex] W = _{V_{i}}^{V_{f}}\int pdV = p(V_{f} - V_{i}) [/tex]
Where:
[tex]V_{f}[/tex]: is the final volume = 31 L
[tex]V_{i}[/tex]: is the initial volume = 63 L
p: is the pressure
Even though we do not have the pressure value, by knowing the values of the initial and final volume we can predict the sign of work.
[tex] W = p(V_{f} - V_{i}) = p(31 L - 63 L) = -32p [/tex]
Therefore, the sign of work will be negative.
I hope it helps you!
