A line is perpendicular to y=3x-8 and intersects the point (6,1). How can we find the slope of this perpendicular line?

Answer:
- [tex]\frac{1}{3}[/tex]
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x - 8 ← is in slope- intercept form
with slope m = 3
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{3}[/tex] ← slope of perpendicular line
Answer:
The Answer is B: We must find the opposite reciprocal of the slope of the line whose equation we were given.
Step-by-step explanation:
I have the same exact question and I also do acellus.