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For the unbalanced reaction below, calculate how many grams of oxygen form when 2.72 g of potassium chlorate completely reacts.

KClO3(s) --> KCl(s) + O2(g)

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MenacingToast

Answer:

1.06g O2

Explanation:

Let's first balance the equation.

2KClO3 > 2KCl + 3O2

We're going to go from:

  1. Grams of KClO3: 2.72g
  2. to moles, using molar mass of KClO3: 122.5g/mol
  3. We'll convert to O2 using a mole ratio, where we have 2 mols of KClO3 to 3 mols of O2.
  4. To grams of O2 using molar mass: 32g/mol

[tex]2.72g x (\frac{1 mol}{122.5g} * \frac{3 mol O2}{2 mol KClO3} * \frac{32g}{1 mol} )= 1.06 g[/tex]

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