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A ball with a mass of 275 g is dropped from rest, hits the floor, and rebounds upward. If the ball hits the floor with a speed of 2.60 m/s, rebounds with a speed of 1.84 m/s, and is in contact with the floor for 1.40 ms,determine the following.
(a) magnitude of the change in the ball's momentum (Let up be in the positive j hat direction.)
_______________kg

Respuesta :

Answer:

-0.209 kg.m/s

Explanation:

The mass of the ball, m = 275g or 0.275 kg

Speed or velocity, v = 2.60 m/s

Momentum, P = mv

Momentum when velocity is 2.60 = 0.275 x 2.60 = 0.715 kg.m/s

Speed or velocity, v = 1.84 m/s

Momentum, P = mv

Momentum when velocity is 1.84= 0.275 x 1.84 = 0.506 kg.m/s

Change in magnitude =  0.506 - 0.715 = -0.209 kg.m/s

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