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A simple random sample of 44 men from a normally distributed population results in a standard deviation of 10.7 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute.a. Identify the null and alternative hypotheses.
b. Compute the test statistic; χ2 = ___ .
c. Find the​ P-value; ​P-value = ____.d. State the conclusion.

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Answer:

Step-by-step explanation:

The Hypothesis :

H0 : σ = 10

H1 : σ ≠ 10

The Chisquare statistic, χ² ;

χ² = [(n-1) * s²] ÷ σ²

Sample size, n = 44 ; sample Standard deviation, s = 10.7 ; population standard deviation, σ = 10

χ² = [(44 - 1) * 10.7²] ÷ 10²

χ² = [43 * 114.49] ÷ 100

χ² = [4923.07] ÷ 100

χ² = 49.2307

Using the Pvalue from Chisquare calculator :

degree of freedom, df = n - 1 = 44 - 1 = 43

Pvalue = 0.238

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