find f(1)' If u know that
g(1)=1 , g'(1)= -1
h(1)= -2 , h'(1) 3

Step-by-step explanation:
[tex]f(x) = g(x)h(x)[/tex]
Taking the derivative of f(x), we get
[tex]f'(x) = g'(x)h(x) + g(x)h'(x)[/tex]
Then [tex]f'(1)[/tex] becomes
[tex]f'(1) = (-1)(-2) + (1)(3) = 5[/tex]