Answer: True
Through the change of base formula, we can say,
[tex]\log_{2}(1) = \frac{\log(1)}{\log(2)} = \frac{0}{\log(2)} = 0[/tex]
So in short,
[tex]\log_{2}(1)=0[/tex]
It turns out that
[tex]\log_{b}(1) = 0[/tex]
for real numbers b such that b > 0 and [tex]b \ne 1[/tex]
