SOMEONE HELP
ASAP PLEASE
Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation.

If y varies directly as x and z, and Y =8/3 when x = 1 and 2 = 4, find y when x = 6 and z = 3.
a.
C.
Y
(03) -
b. y = x; }(6, 3) 27
27
2
vx; (6, 3) =24
» -«xz; "(0, 3) =12
d.

SOMEONE HELP ASAP PLEASE Find the constant of variation for the relation and use it to write an equation for the statement Then solve the equation If y varies d class=

Respuesta :

Answer:

D

Step-by-step explanation:

Given y varies directly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = [tex]\frac{8}{3}[/tex] when x = 1 and z = 4 , then

[tex]\frac{8}{3}[/tex] = k × 1 × 4 = 4k ( divide both sides by 4 )

[tex]\frac{2}{3}[/tex] = k

y = [tex]\frac{2}{3}[/tex] xz ← equation of variation

When x = 6 and z = 3 , then

y = [tex]\frac{2}{3}[/tex] × 6 × 3 = [tex]\frac{2}{3}[/tex] × 18 = 2 × 6 = 12

Answer:

the answer to this question is

d.)y=⅔xz;y(6,3)=12