Answer:
[tex](x,y) = (\frac{27}{4}, -\frac{1}{2})[/tex]
Explanation:
Given
[tex](x_1,y_1) = (3,-2)[/tex]
[tex](x_2,y_2) = (8,0)[/tex]
[tex]m : n = 3 :1[/tex]
Required
The coordinates of the point
This is calculated using:
[tex](x,y) = \frac{1}{m+n}(mx_2 + nx_1, my_2 + ny_1)[/tex]
So, we have:
[tex](x,y) = \frac{1}{3+1}(3*8 + 1*3, 3*0 - 1*2)[/tex]
[tex](x,y) = \frac{1}{4}(27, -2)[/tex]
So, we have:
[tex](x,y) = (\frac{27}{4}, -\frac{1}{2})[/tex]
