Answer:
The given relation is presented as follows;
[tex]\dfrac{1}{a} + \dfrac{1}{b} +\dfrac{1}{c} = \dfrac{1}{a + b + c}[/tex]
Where 'a', 'b', and 'c' are member of real numbers, we have;
a⁹, b⁹, and c⁹ are also member of real numbers
When a⁹ = x, b⁹ = y, and c⁹ = z
By the above relationship, we have;
[tex]\dfrac{1}{x} + \dfrac{1}{y} +\dfrac{1}{z} = \dfrac{1}{x + y + z}[/tex]
Substituting x = a⁹, y = b⁹, and z = c⁹, we get;
[tex]\dfrac{1}{a^9} + \dfrac{1}{b^9} +\dfrac{1}{c^9} = \dfrac{1}{a^9 + b^9 + c^9}[/tex]
Step-by-step explanation:
