Answer:
The general limit exists at x = 9 and is equal to 300.
Step-by-step explanation:
We want to find the general limit of the function:
[tex]\displaystyle \lim_{x \to 9}(x^2+2^7+(9.1\times 10))[/tex]
By definition, a general limit exists at a point if the two one-sided limits exist and are equivalent to each other.
So, let's find each one-sided limit: the left-hand side and the right-hand side.
The left-hand limit is given by:
[tex]\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))[/tex]
Since the given function is a polynomial, we can use direct substitution. This yields:
[tex]=(9)^2+2^7+(9.1\times 10)[/tex]
Evaluate:
[tex]300[/tex]
Therefore:
[tex]\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))=300[/tex]
The right-hand limit is given by:
[tex]\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))[/tex]
Again, since the function is a polynomial, we can use direct substitution. This yields:
[tex]=(9)^2+2^7+(9.1\times 10)[/tex]
Evaluate:
[tex]=300[/tex]
Therefore:
[tex]\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300[/tex]
Thus, we can see that:
[tex]\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1\times 10))=\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300[/tex]
Since the two-sided limits exist and are equivalent, the general limit of the function does exist at x = 9 and is equal to 300.
