A final statistics exam had a mean of 70 and a variance of 25. If Bruce earned an 80 on his exam, what is his score?

Respuesta :

Answer:

2

Step-by-step explanation:

Value = 80

Mean = 70

Variance = 25

Standard deviation=root(Variance)=root(25)=5

z score = (value - mean)/standard deviation

            = (80-70)/5

            = 10/5

            = 2

z-score using mean 70 and variance 25 is 2

Given :

A final statistics exam had a mean of 70 and a variance of 25

First we find out standard deviation using variance

standard deviation =[tex]\sqrt{variance} =\sqrt{25} =5[/tex]

Now we find out z-score

[tex]z-score =\frac{value - mean}{standard \; deviation }[/tex]

value =80

mean=70 and standard deviation =5

substitute all the values

[tex]z-score = \frac{80-70}{5} =2[/tex]

So, his z-score using mean and variance is 2

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