Lead time for computers is 5 days with daily demand of 25 and safety stock of 15 computers. If management wants to use 10 kanbans how many computers should each one hold?
A) 25.
B) 1.
C) 5.
D) 10.
E) 13.

Respuesta :

Answer:

Option E (13) is the correct answer.

Explanation:

According to the question, the values are:

Daily demand,

d = 25

Safety stock,

S = 5

Lead time,

L = 5

Number of kanbans,

N = 10

Now,

The formula is:

⇒ [tex]N=\frac{dL+S}{C}[/tex]

By putting the values, we get

⇒ [tex]10=\frac{25\times 5+5}{C}[/tex]

⇒ [tex]10=\frac{130}{C}[/tex]

⇒ [tex]C=\frac{130}{10}[/tex]

⇒     [tex]=13[/tex]

Number of computer each one hold is 14 computers

Given that;

Lead time = 5 days

Safety stock = 15 computers

Daily demand = 25 computers

Find:

Number of computer each one hold

Computation:

Total demand = 25 × 5 = 125

Total number of computers = 125 + 15

Total number of computers = 140 computers

Total number of kanbans = 10 kanbans

Number of computer each one hold = 140 / 10

Number of computer each one hold = 14 computers

Computation:

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