Answer:
The correct solution is "93.48 M".
Explanation:
According to the question,
The number of moles of NaOH will be:
= [tex]0.753\times 38.5[/tex]
= [tex]28.99 \ mol[/tex]
The number of moles of needed [tex]H_2SO_4[/tex] will be:
= [tex]\frac{1}{2}\times 28.99[/tex]
= [tex]14.49 \ mol[/tex]
hence,
The concentration of [tex]H_2SO_4[/tex] solution will be:
= [tex]\frac{Number \ of \ moles}{Volume \ of \ solution}[/tex]
= [tex]\frac{14.49}{0.155}[/tex]
= [tex]93.48 \ M[/tex]
