Answer: [tex]75.47\ ft[/tex]
Step-by-step explanation:
Given
String of the kite is [tex]l=100\ ft[/tex]
Angle of elevation [tex]\theta=49^{\circ}[/tex]
suppose altitude of the kite is h
from the figure, we can write
[tex]\Rightarrow \sin 49^{\circ}=\dfrac{h}{100}\\\\\Rightarrow h=100\sin 49^{\circ}\\\\\Rightarrow h=75.47\ ft[/tex]
Thus, the altitude of the kite is [tex]75.47\ ft[/tex]
