Answer:
969.6 kPa
Explanation:
Applying,
P/T = P'/T'..................... Equation 1
Where P = Initial pressure of the gas, T = Initial temperature of the gas, P' = Final pressure of the gas, T' = Final temperature of the gas
make P' the subject of the equation
P' = PT'/T................. Equation 2
From the question,
Given: P = 121.2 kPa, T' = 2111°C = (273+2111) = 2384 K, T = 25°C = (273+25) K = 298 K
Substitute these values into equation 2
P' = (121.2×2384)298
P' = 969.6 kPa
