Step-by-step explanation:
The path followed by the ball as a function of time is given by :
[tex]h=-16t^2+vt+h[/tex]
Where
v is initial velocity and h is initial height,
v = 4.3 cm/s = 0.043 m/s and h = 14 cm = 0.14 m
The equation becomes,
[tex]h=-16t^2+0.043t+0.14[/tex] ....(1)
It is a quadratic equation,
t = 0.095 s
Put the value of t in equation (1).
[tex]h=-16(0.095)^2+0.043(0.095)+0.14\\\\h=-0.000315\ m[/tex]
or
h = -0.00103 ft (negative sign shows height is in negative direction)
