Answer:
HL
Step-by-step explanation:
We know the following:
The hypotenuse, DB, of ∆BAD is congruent to the hypotenuse, CA, of ∆CBA.
Also, a leg, AB in ∆BAD is congruent to a leg, AB in ∆CBA.
This shows that the hypotenuse and a leg of ∆CBA is congruent to the hypotenuse and the corresponding leg of ∆BAD. Based on the Hypotenuse-Leg Theorem, both triangles are congruent.
