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For the love of God please help me before my mom gets angry about my horrible grades
A 170.0 g sample of a substance is heated to 120.0 °C and then plunged into 200.0 mL of water at 10.0 °C. The resulting mixture has a temperature of 12.6 °C. What is the specific heat capacity of the substance?
I'LL GIVE BRAINLIEST!!!!

Respuesta :

Answer:

Heat Lost = (120 - 12.6) deg * 170 g * S = `18260 gm-deg * S

Heat Gained = (12.6 - 10) deg * 200 gm* 1 cal/ gm-deg - 520 cal

S = 520 / 18260 cal / gm-deg = .0285 cal / gm-deg

Since Heat Lost = Heat Gained

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