Answer:
The emf amplitude in the secondary coil is 26.53 V
Explanation:
Given that,
The number of turns of the primary coil of a transformer = 441
The number of turns of the secondary coil of a transformer = 1000
The emf in the primary is of amplitude 11.7 V
We need to find the emf amplitude in the secondary. We know that,
[tex]\dfrac{E_1}{N_1}=\dfrac{E_2}{N_2}\\\\E_2=\dfrac{E_1N_2}{N_1}[/tex]
Put all the values,
[tex]E_2=\dfrac{11.7\times 1000}{441}\\\\E_2=26.53\ V[/tex]
So, the emf amplitude in the secondary coil is 26.53 V.
