The acceleration is 1.2 m/s^2. The distance travelled is 1197 m. The time taken is 44.7 seconds.
The rate at which the velocity changes is called the acceleration of the body.
Given that;
v = u - at
v = 0 m/s because the car comes to stop
u = at
a = u/t
a = 53.6 m/s/ 45 seconds
a = 1.2 m/s^2
The distance travelled is;
v^2 = u^2 - 2as
v = 0 m/s
u^2 = 2as
s = u^2/2a
a = ( 53.6 )^2/2 * 1.2
s = 1197 m
Time taken to stop is obtained from;
v = u - at
when v = 0 m/s
u = at
t = u/a
t = 53.6/1.2
t = 44.7 seconds
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