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Find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. (Round your answer to four decimal places. Enter your answers as a comma-separated list.) (See attachment)

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Find the values of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval Round your answer to four decimal places Enter class=

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Answer:

Step-by-step explanation:

f'(x)=-sin x

[tex]f'(x)=\frac{cos \frac{\pi }{3} -cos (\frac{-\pi }{3}) }{\frac{\pi }{3} -(\frac{-\pi }{3}) } \\-sin x=\frac{\frac{1}{2} -\frac{1}{2} }{\frac{\pi }{3} +\frac{\pi }{3} } \\sin x=0\\at x=c ,sin c=0,c=0[/tex]

c=0∈(-π/3,π/3)

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