Answer:
Center: [tex](-2, 3)[/tex]
Radius: [tex]4[/tex]
Equation of circle: [tex](x+2)^2+(y-3)^2=16[/tex]
Step-by-step explanation:
The equation of a circle with radius [tex]r[/tex] and center [tex](h, k)[/tex] is given by:
[tex](x-h)^2+(y-k)^2=r^2[/tex].
What we've found:
- radius of [tex]4[/tex]
- center at [tex](-2,3)[/tex]
Substituting given values, we get:
[tex](x-(-2))^2+(y-3)^2=4^2,\\\boxed{(x+2)^2+(y-3)^2=16}[/tex]
