Answer:
1. 2.510kJ
2. Q = 1.5 kJ
Explanation:
Hello there!
In this case, according to the given information for this calorimetry problem, we can proceed as follows:
1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:
[tex]1cal=4.184J\\\\1kJ=1000J[/tex]
Then, we perform the conversion as follows:
[tex]600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ[/tex]
2. Here, we use the general heat equation:
[tex]Q=mC(T_2-T_1)[/tex]
And we plug in the given mass, specific heat and initial and final temperature to obtain:
[tex]Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ[/tex]
Regards!