Answer:
57.12 cm²
Step-by-step explanation:
The given dimensions of the hexagon are;
The side length of the hexagon, s = 5 cm
The distance across flats = 8 cm
The distance across corners = 9.28 cm
The area of a regular hexagon, 'A', is given as follows;
[tex]A = \dfrac{3 \cdot \sqrt{3} }{2} \cdot s^2= \dfrac{1}{2} \cdot P \cdot a = 3\cdot s\cdot h[/tex]
Where;
a = The side length of the hexagon
P = The perimeter of the hexagon
h = The height of one of the triangles in the hexagon
However with the given dimensions, the area of the hexagon can be found by finding the sum of the areas of the triangles that make up the rectangle
A₁ = A₃ = A₄ = A₆ = (1/2) × 4.64 cm × 4 cm = 9.28 cm²
A₂ = A₅ = (1/2) × 5 cm × 4 cm = 10 cm₂
The area of the hexagon, A = A₁ + A₃+ A₄ + A₆ + A₂ + A₅ = 4 × A₁ + 2 × A₂
∴ A = 4 × 9.28 cm² + 2 × 10 cm² = 57.12 cm²
2 × (5×4/2 + 2×9.28/4×4) = 57.12 cm²
The area of the hexagon, A = 57.12 cm²
