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If the scores per round of golfers on the PGA tour are approximately normally distributed with mean 69.3 and standard deviation 2.58, what is the probability that a randomly chosen golfer's score is below 70 strokes

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Answer:

0.6069

Step-by-step explanation:

Given an approximately normal distribution:

Z = (x - mean) / standard deviation

Mean = 69.3 ; Standard deviation = 2.58

For :

P(x < 70)

Z = (70 - 69.3) / 2.58

Z = 0.7 / 2.58

Z = 0.2713

P(Z < 0.2713) = 0.6069

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