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The side length of an isosceles right triangle is 7x + 3 feet. (both base and height are 7x + 3 feet).

then written in standard form, what is the area of the triangle? (area of triangle = 1/2bh)

What is the area of the triangle in cubic feet when x = 11?

Respuesta :

sqdancefan

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Answer:

  • area: 49/2x^2 +21x +9/2
  • for x=11: 3200 ft^2

Step-by-step explanation:

The area is given by the formula in the problem statement:

  A = 1/2bh

  A = 1/2(7x +3)(7x +3) = 1/2(49x^2 +42x +9)

The area is (49/2)x^2 +21x +9/2 . . . square feet.

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When x=11, the area is ...

  A = (1/2)(7·11 +3)^2 = 1/2(80^2) = 3200 . . . . square feet

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Comment on the problem statement

Area is measured in square feet, not cubic feet.

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