In any equation with variables, you want to end with a variable isolated on one side with no coefficients(like x=4, for instance).
So, with that in mind, let's solve number 2.
5(x-3) - 2(2x+4) = -2(x-2)
Let's distribute the coefficients.
(5x-15)-(4x+8) = (-2x+4)
Simplify the left side first (by subtracting the two)
5x-4x = x
-15 - (+)8 = -23
So, left side is
x-23 = -2x+4
We're close now, just bring the x to the left side and the other values to the right
x-23 = -2x+4
+23 +23
x=-2x+27
+2x +2x
3x=27
divide by 3
x=9
3.
3(4x-5)-2(2x-2)=4(3x-2)+5
Same idea here; distribute the coefficients, and simplify.
(12x-15)-(4x-4)=(12x-8)+5
12x-4x=8x
-15-(-)4=-11
-8+5=-3
8x-11=12x-3
bring x to left, other numbers to right
-12x -12x
+11 +11
-4x = 8
divide by -4
x=-2
