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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using the equation, what height was the rocket launched from? y=-16x^2+57x+32

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sqdancefan

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Answer:

  32 feet

Step-by-step explanation:

0 seconds after launch, the rocket is still sitting on the tower. Its height is...

  y = -16(0^2) +57(0) +32

  y = 0 + 0 + 32 = 32

The rocket was launched from a tower 32 feet high.

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