Answer:
Roots: 0.79 and 3.79
Step-by-step explanation:
[tex]x^2 + 3x - 3 = 0\\a=1\,,\ \ b=3\,,\ \ c=-3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-3\pm\sqrt{3^2-4\cdot1\cdot(-3)}}{2\cdot1}=\dfrac{-3\pm\sqrt{9+12}}{2}=\dfrac{-3\pm\sqrt{21}}{2}\\\\x\approx0.79\quad or\quad x\approx3.79[/tex]
