Answer:
[tex]\sum\limits^5_{n=1} {2^{n-2}} = 15.5[/tex]
Step-by-step explanation:
Given
[tex]\sum\limits^5_{n=1} {2^{n-2}[/tex]
Required
The result
To do this, we simply substitute 1 to 5 for n.
So, we have:
[tex]\sum\limits^5_{n=1} {2^{n-2}} = 2^{1-2} + 2^{2-2} + 2^{3-2} + 2^{4-2} + 2^{5-2}[/tex]
[tex]\sum\limits^5_{n=1} {2^{n-2}} = 2^{-1} + 2^{0} + 2^{1} + 2^{2} + 2^{3}[/tex]
Evaluate each exponent
[tex]\sum\limits^5_{n=1} {2^{n-2}} = 0.5 + 1 + 2 + 4 +8[/tex]
[tex]\sum\limits^5_{n=1} {2^{n-2}} = 15.5[/tex]
